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  一些精彩的SQL代码   作者:本站整理 2009-9-1 11:17:45  

  作为一名programmer,积累代码是很重要的。下面是我从网上搜集得到的一些精彩的SQL代码,可以作为平常编写SQL代码时做参考之用。

------------------------------------

  • 说明:复制表(只复制结构,源表名:a 新表名:b)
    select * into b from a where 1<>1
  • 说明:拷贝表(拷贝数据,源表名:a 目标表名:b)
    insert into b(a, b, c) select d,e,f from b;
  • 说明:显示文章、提交人和最后回复时间
    select a.title,a.username,b.adddate from table a,(select max(adddate) adddate from table where table.title=a.title) b
  • 说明:外连接查询(表名1:a 表名2:b)
    select a.a, a.b, a.c, b.c, b.d, b.f from a LEFT OUT JOIN b ON a.a = b.c
  • 说明:日程安排提前五分钟提醒
    select * from 日程安排 where datediff(’minute’,f开始时间,getdate())>5
  • 说明:两张关联表,删除主表中已经在副表中没有的信息
    delete from info where not exists ( select * from infobz where info.infid=infobz.infid )
  • 说明:– SQL:SELECT A.NUM, A.NAME, B.UPD_DATE, B.PREV_UPD_DATE

    FROM TABLE1,

    (SELECT X.NUM, X.UPD_DATE, Y.UPD_DATE PREV_UPD_DATE

    FROM (SELECT NUM, UPD_DATE, INBOUND_QTY, STOCK_ONHAND

    FROM TABLE2

    WHERE TO_CHAR(UPD_DATE,’YYYY/MM’) = TO_CHAR(SYSDATE, ‘YYYY/MM’)) X,

    (SELECT NUM, UPD_DATE, STOCK_ONHAND

    FROM TABLE2

    WHERE TO_CHAR(UPD_DATE,’YYYY/MM’) =

    TO_CHAR(TO_DATE(TO_CHAR(SYSDATE, ‘YYYY/MM’) || ‘/01′,’YYYY/MM/DD’) - 1, ‘YYYY/MM’) ) Y,

    WHERE X.NUM = Y.NUM (+)

    AND X.INBOUND_QTY + NVL(Y.STOCK_ONHAND,0) <> X.STOCK_ONHAND ) B

    WHERE A.NUM = B.NUM

  • 说明:–
    select * from studentinfo where not exists(select * from student where studentinfo.id=student.id) and 系名称=’”&strdepartmentname&”‘ and 专业名称=’”&strprofessionname&”‘ order by 性别,生源地,高考总成绩
  • 从数据库中去一年的各单位电话费统计(电话费定额贺电化肥清单两个表来源) SELECT a.userper, a.tel, a.standfee, TO_CHAR(a.telfeedate, ‘yyyy’) AS telyear,SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘01′, a.factration)) AS JAN,

    SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘02′, a.factration)) AS FRI,

    SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘03′, a.factration)) AS MAR,

    SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘04′, a.factration)) AS APR,

    SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘05′, a.factration)) AS MAY,

    SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘06′, a.factration)) AS JUE,

    SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘07′, a.factration)) AS JUL,

    SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘08′, a.factration)) AS AGU,

    SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘09′, a.factration)) AS SEP,

    SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘10′, a.factration)) AS OCT,

    SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘11′, a.factration)) AS NOV,

    SUM(decode(TO_CHAR(a.telfeedate, ‘mm’), ‘12′, a.factration)) AS DEC

    FROM (SELECT a.userper, a.tel, a.standfee, b.telfeedate, b.factration

    FROM TELFEESTAND a, TELFEE b

    WHERE a.tel = b.telfax) a

    GROUP BY a.userper, a.tel, a.standfee, TO_CHAR(a.telfeedate, ‘yyyy’)

  • 说明:四表联查问题
    select * from a left inner join b on a.a=b.b right inner join c on a.a=c.c inner join d on a.a=d.d where …..
  • 说明:得到表中最小的未使用的ID号
  • SELECT (CASE WHEN EXISTS(SELECT * FROM Handle b WHERE b.HandleID = 1) THEN MIN(HandleID) + 1 ELSE 1 END) as HandleID FROM Handle WHERE NOT HandleID IN (SELECT a.HandleID - 1 FROM Handle a)
  • 一个SQL语句的问题:行列转换
    select * from v_temp
    上面的视图结果如下:
    user_name role_name
    ————————-
    系统管理员 管理员
    feng 管理员
    feng 一般用户
    test 一般用户
    想把结果变成这样:
    user_name role_name
    —————————
    系统管理员 管理员
    feng 管理员,一般用户
    test 一般用户
    ===================
    create table a_test(name varchar(20),role2 varchar(20))
    insert into a_test values(’李’,’管理员’)
    insert into a_test values(’张’,’管理员’)
    insert into a_test values(’张’,’一般用户’)
    insert into a_test values(’常’,’一般用户’) create function join_str(@content varchar(100))
    returns varchar(2000)
    as
    begin
    declare @str varchar(2000)
    set @str=”
    select @str=@str+’,’+rtrim(role2) from a_test where [name]=@content
    select @str=right(@str,len(@str)-1)
    return @str
    end
    go

    –调用:
    select [name],dbo.join_str([name]) role2 from a_test group by [name]

    –select distinct name,dbo.uf_test(name) from a_test

  • 快速比较结构相同的两表
    结构相同的两表,一表有记录3万条左右,一表有记录2万条左右,我怎样快速查找两表的不同记录?
    ============================
    给你一个测试方法,从northwind中的orders表取数据。
    select * into n1 from orders
    select * into n2 from orders select * from n1
    select * from n2

    –添加主键,然后修改n1中若干字段的若干条
    alter table n1 add constraint pk_n1_id primary key (OrderID)
    alter table n2 add constraint pk_n2_id primary key (OrderID)

    select OrderID from (select * from n1 union select * from n2) a group by OrderID having count(*) > 1

    应该可以,而且将不同的记录的ID显示出来。
    下面的适用于双方记录一样的情况,

    select * from n1 where orderid in (select OrderID from (select * from n1 union select * from n2) a group by OrderID having count(*) > 1)
    至于双方互不存在的记录是比较好处理的
    –删除n1,n2中若干条记录
    delete from n1 where orderID in (’10728′,’10730′)
    delete from n2 where orderID in (’11000′,’11001′)

    –*************************************************************
    – 双方都有该记录却不完全相同
    select * from n1 where orderid in(select OrderID from (select * from n1 union select * from n2) a group by OrderID having count(*) > 1)
    union
    –n2中存在但在n1中不存的在10728,10730
    select * from n1 where OrderID not in (select OrderID from n2)
    union
    –n1中存在但在n2中不存的在11000,11001
    select * from n2 where OrderID not in (select OrderID from n1)

  • 四种方法取表里n到m条纪录:1.
    select top m * into 临时表(或表变量) from tablename order by columnname — 将top m笔插入
    set rowcount n
    select * from 表变量 order by columnname desc2.
    select top n * from (select top m * from tablename order by columnname) a order by columnname desc

    3.如果tablename里没有其他identity列,那么:
    select identity(int) id0,* into #temp from tablename

    取n到m条的语句为:
    select * from #temp where id0 >=n and id0 <= m

    如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行:
    exec sp_dboption 你的DB名字,’select into/bulkcopy’,true

    4.如果表里有identity属性,那么简单:
    select * from tablename where identitycol between n and m

  • 如何删除一个表中重复的记录?
    create table a_dist(id int,name varchar(20)) insert into a_dist values(1,’abc’)
    insert into a_dist values(1,’abc’)
    insert into a_dist values(1,’abc’)
    insert into a_dist values(1,’abc’)

    exec up_distinct ‘a_dist’,’id’

    select * from a_dist

    create procedure up_distinct(@t_name varchar(30),@f_key varchar(30))
    –f_key表示是分组字段﹐即主键字段
    as
    begin
    declare @max integer,@id varchar(30) ,@sql varchar(7999) ,@type integer
    select @sql = ‘declare cur_rows cursor for select ‘+@f_key+’ ,count(*) from ‘ +@t_name +’ group by ‘ +@f_key +’ having count(*) > 1′
    exec(@sql)
    open cur_rows
    fetch cur_rows into @id,@max
    while @@fetch_status=0
    begin
    select @max = @max -1
    set rowcount @max
    select @type = xtype from syscolumns where id=object_id(@t_name) and name=@f_key
    if @type=56
    select @sql = ‘delete from ‘+@t_name+’ where ‘ + @f_key+’ = ‘+ @id
    if @type=167
    select @sql = ‘delete from ‘+@t_name+’ where ‘ + @f_key+’ = ‘+””+ @id +””
    exec(@sql)
    fetch cur_rows into @id,@max
    end
    close cur_rows
    deallocate cur_rows
    set rowcount 0
    end

    select * from systypes
    select * from syscolumns where id = object_id(’a_dist’)

  • 查询数据的最大排序问题(只能用一条语句写)
    CREATE TABLE hard (qu char (11) ,co char (11) ,je numeric(3, 0)) insert into hard values (’A’,’1′,3)
    insert into hard values (’A’,’2′,4)
    insert into hard values (’A’,’4′,2)
    insert into hard values (’A’,’6′,9)
    insert into hard values (’B’,’1′,4)
    insert into hard values (’B’,’2′,5)
    insert into hard values (’B’,’3′,6)
    insert into hard values (’C’,’3′,4)
    insert into hard values (’C’,’6′,7)
    insert into hard values (’C’,’2′,3)

    要求查询出来的结果如下:

    qu co je
    ———– ———– —–
    A 6 9
    A 2 4
    B 3 6
    B 2 5
    C 6 7
    C 3 4

    就是要按qu分组,每组中取je最大的前2位!!
    而且只能用一句sql语句!!!
    select * from hard a where je in (select top 2 je from hard b where a.qu=b.qu order by je)

  • 求删除重复记录的sql语句?
    怎样把具有相同字段的纪录删除,只留下一条。
    例如,表test里有id,name字段
    如果有name相同的记录 只留下一条,其余的删除。
    name的内容不定,相同的记录数不定。
    有没有这样的sql语句?
    ==============================
    A:一个完整的解决方案: 将重复的记录记入temp1表:
    select [标志字段id],count(*) into temp1 from [表名]
    group by [标志字段id]
    having count(*)>1

    2、将不重复的记录记入temp1表:
    insert temp1 select [标志字段id],count(*) from [表名] group by [标志字段id] having count(*)=1

    3、作一个包含所有不重复记录的表:
    select * into temp2 from [表名] where 标志字段id in(select 标志字段id from temp1)

    4、删除重复表:
    delete [表名]

    5、恢复表:
    insert [表名] select * from temp2

    6、删除临时表:
    drop table temp1
    drop table temp2
    ================================
    B:
    create table a_dist(id int,name varchar(20))

    insert into a_dist values(1,’abc’)
    insert into a_dist values(1,’abc’)
    insert into a_dist values(1,’abc’)
    insert into a_dist values(1,’abc’)

    exec up_distinct ‘a_dist’,’id’

    select * from a_dist

    create procedure up_distinct(@t_name varchar(30),@f_key varchar(30))
    –f_key表示是分组字段﹐即主键字段
    as
    begin
    declare @max integer,@id varchar(30) ,@sql varchar(7999) ,@type integer
    select @sql = ‘declare cur_rows cursor for select ‘+@f_key+’ ,count(*) from ‘ +@t_name +’ group by ‘ +@f_key +’ having count(*) > 1′
    exec(@sql)
    open cur_rows
    fetch cur_rows into @id,@max
    while @@fetch_status=0
    begin
    select @max = @max -1
    set rowcount @max
    select @type = xtype from syscolumns where id=object_id(@t_name) and name=@f_key
    if @type=56
    select @sql = ‘delete from ‘+@t_name+’ where ‘ + @f_key+’ = ‘+ @id
    if @type=167
    select @sql = ‘delete from ‘+@t_name+’ where ‘ + @f_key+’ = ‘+””+ @id +””
    exec(@sql)
    fetch cur_rows into @id,@max
    end
    close cur_rows
    deallocate cur_rows
    set rowcount 0
    end

    select * from systypes
    select * from syscolumns where id = object_id(’a_dist’)

  • 行列转换–普通 假设有张学生成绩表(CJ)如下
    Name Subject Result
    张三 语文 80
    张三 数学 90
    张三 物理 85
    李四 语文 85
    李四 数学 92
    李四 物理 82想变成
    姓名 语文 数学 物理
    张三 80 90 85
    李四 85 92 82

    declare @sql varchar(4000)
    set @sql = ’select Name’
    select @sql = @sql + ‘,sum(case Subject when ”’+Subject+”’ then Result end) [’+Subject+’]‘
    from (select distinct Subject from CJ) as a
    select @sql = @sql+’ from test group by name’
    exec(@sql)

    行列转换–合并

    有表A,
    id pid
    1 1
    1 2
    1 3
    2 1
    2 2
    3 1
    如何化成表B:
    id pid
    1 1,2,3
    2 1,2
    3 1

    创建一个合并的函数
    create function fmerg(@id int)
    returns varchar(8000)
    as
    begin
    declare @str varchar(8000)
    set @str=”
    select @str=@str+’,’+cast(pid as varchar) from 表A where id=@id
    set @str=right(@str,len(@str)-1)
    return(@str)
    End
    go

    –调用自定义函数得到结果
    select distinct id,dbo.fmerg(id) from 表A

  • 如何取得一个数据表的所有列名 方法如下:先从SYSTEMOBJECT系统表中取得数据表的SYSTEMID,然后再SYSCOLUMN表中取得该数据表的所有列名。
    SQL语句如下:
    declare @objid int,@objname char(40)
    set @objname = ‘tablename’
    select @objid = id from sysobjects where id = object_id(@objname)
    select ‘Column_name’ = name from syscolumns where id = @objid order by colid或

    SELECT * FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME =’users’

  • 通过SQL语句来更改用户的密码 修改别人的,需要sysadmin role
    EXEC sp_password NULL, ‘newpassword’, ‘User’如果帐号为SA执行EXEC sp_password NULL, ‘newpassword’, sa
  • 怎么判断出一个表的哪些字段不允许为空? select COLUMN_NAME from INFORMATION_SCHEMA.COLUMNS where IS_NULLABLE=’NO’ and TABLE_NAME=tablename
  • 如何在数据库里找到含有相同字段的表?
    a. 查已知列名的情况
    SELECT b.name as TableName,a.name as columnname
    From syscolumns a INNER JOIN sysobjects b
    ON a.id=b.id
    AND b.type=’U’
    AND a.name=’你的字段名字’
  • 未知列名查所有在不同表出现过的列名
    Select o.name As tablename,s1.name As columnname
    From syscolumns s1, sysobjects o
    Where s1.id = o.id
    And o.type = ‘U’
    And Exists (
    Select 1 From syscolumns s2
    Where s1.name = s2.name
    And s1.id <> s2.id
    )
  • 查询第xxx行数据 假设id是主键:
    select * from (select top xxx * from yourtable) aa where not exists(select 1 from (select top xxx-1 * from yourtable) bb where aa.id=bb.id)如果使用游标也是可以的
    fetch absolute [number] from [cursor_name]
    行数为绝对行数
  • SQL Server日期计算
    a. 一个月的第一天
    SELECT DATEADD(mm, DATEDIFF(mm,0,getdate()), 0)
    b. 本周的星期一
    SELECT DATEADD(wk, DATEDIFF(wk,0,getdate()), 0)
    c. 一年的第一天
    SELECT DATEADD(yy, DATEDIFF(yy,0,getdate()), 0)
    d. 季度的第一天
    SELECT DATEADD(qq, DATEDIFF(qq,0,getdate()), 0)
    e. 上个月的最后一天
    SELECT dateadd(ms,-3,DATEADD(mm, DATEDIFF(mm,0,getdate()), 0))
    f. 去年的最后一天
    SELECT dateadd(ms,-3,DATEADD(yy, DATEDIFF(yy,0,getdate()), 0))
    g. 本月的最后一天
    SELECT dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,getdate())+1, 0))
    h. 本月的第一个星期一
    select DATEADD(wk, DATEDIFF(wk,0,
    dateadd(dd,6-datepart(day,getdate()),getdate())
    ), 0)
    i. 本年的最后一天
    SELECT dateadd(ms,-3,DATEADD(yy, DATEDIFF(yy,0,getdate())+1, 0))。
  • 获取表结构[把 ’sysobjects’ 替换 成 ’tablename’ 即可] SELECT CASE IsNull(I.name, ”)
    When ” Then ”
    Else ‘*’
    End as IsPK,
    Object_Name(A.id) as t_name,
    A.name as c_name,
    IsNull(SubString(M.text, 1, 254), ”) as pbc_init,
    T.name as F_DataType,
    CASE IsNull(TYPEPROPERTY(T.name, ‘Scale’), ”)
    WHEN ” Then Cast(A.prec as varchar)
    ELSE Cast(A.prec as varchar) + ‘,’ + Cast(A.scale as varchar)
    END as F_Scale,
    A.isnullable as F_isNullAble
    FROM Syscolumns as A
    JOIN Systypes as T
    ON (A.xType = T.xUserType AND A.Id = Object_id(’sysobjects’) )
    LEFT JOIN ( SysIndexes as I
    JOIN Syscolumns as A1
    ON ( I.id = A1.id and A1.id = object_id(’sysobjects’) and (I.status & 0×800) = 0×800 AND A1.colid <= I.keycnt) )
    ON ( A.id = I.id AND A.name = index_col(’sysobjects’, I.indid, A1.colid) )
    LEFT JOIN SysComments as M
    ON ( M.id = A.cdefault and ObjectProperty(A.cdefault, ‘IsConstraint’) = 1 )
    ORDER BY A.Colid ASC
  • 提取数据库内所有表的字段详细说明的SQL语句 SELECT
    (case when a.colorder=1 then d.name else ” end) N’表名’,
    a.colorder N’字段序号’,
    a.name N’字段名’,
    (case when COLUMNPROPERTY( a.id,a.name,’IsIdentity’)=1 then ‘√’else ”
    end) N’标识’,
    (case when (SELECT count(*)
    FROM sysobjects
    WHERE (name in
    (SELECT name
    FROM sysindexes
    WHERE (id = a.id) AND (indid in
    (SELECT indid
    FROM sysindexkeys
    WHERE (id = a.id) AND (colid in
    (SELECT colid
    FROM syscolumns
    WHERE (id = a.id) AND (name = a.name))))))) AND
    (xtype = ‘PK’))>0 then ‘√’ else ” end) N’主键’,
    b.name N’类型’,
    a.length N’占用字节数’,
    COLUMNPROPERTY(a.id,a.name,’PRECISION’) as N’长度’,
    isnull(COLUMNPROPERTY(a.id,a.name,’Scale’),0) as N’小数位数’,
    (case when a.isnullable=1 then ‘√’else ” end) N’允许空’,
    isnull(e.text,”) N’默认值’,
    isnull(g.[value],”) AS N’字段说明’
    FROM syscolumns a
    left join systypes b
    on a.xtype=b.xusertype
    inner join sysobjects d
    on a.id=d.id and d.xtype=’U’ and d.name<>’dtproperties’
    left join syscomments e
    on a.cdefault=e.id
    left join sysproperties g
    on a.id=g.id AND a.colid = g.smallid
    order by object_name(a.id),a.colorder
  • 快速获取表test的记录总数[对大容量表非常有效] 快速获取表test的记录总数:
    select rows from sysindexes where id = object_id(’test’) and indid in (0,1)update 2 set KHXH=(ID+1)\2 2行递增编号
    update [23] set id1 = ‘No.’+right(’00000000′+id,6) where id not like ‘No%’ //递增
    update [23] set id1= ‘No.’+right(’00000000′+replace(id1,’No.’,”),6) //补位递增
    delete from [1] where (id%2)=1
    奇数
  • 替换表名字段
    update [1] set domurl = replace(domurl,’Upload/Imgswf/’,’Upload/Photo/’) where domurl like ‘%Upload/Imgswf/%’
  • 截位
    SELECT LEFT(表名, 5)

  另:

  ----------------------------------

  1.把某个字段重新生气序列(从1到n):
  DECLARE @i int
  Set @i = 0
  Update Table1 Set @i = @i + 1,Field1 = @i

  2.按成绩排名次
  Update 成绩表
  Set a.名次 = (
  Select Count(*) + 1
  From 成绩表 b
  Where a.总成绩 < b.总成绩
  )
  From 成绩表 a

  3.查询外部数据库
  Select a.* From OpenRowSet(’Microsoft.Jet.OLEDB.4.0′,’c:\test.mdb’;’admin’;”,Table1) a

  4.查询Excel文件
  Select * From OpenDataSource(’Microsoft.Jet.OLEDB.4.0′,’Data Source=”c:\test.xls”;User ID=Admin;Password=;Extended properties=Excel 8.0′)…Sheet1$

  5.在查询中指定排序规则
  Select * From Table1 Order By Field1 COLLATE Chinese_PRC_BIN
  为什么要指定排序规则呢?参见:
  http://www.delphibbs.com/delphibbs/dispq.asp?lid=1633985
  例,检查数据库中的Pub_Users表中是否存在指定的用户:
  Select Count(*) From Pub_Users Where [UserName]=’admin’ And [PassWord]=’aaa’ COLLATE Chinese_PRC_BIN
  默认比较是不区分大小写的,如果不加COLLATE Chinese_PRC_BIN,那么密码aaa与AAA是等效的,这当然与实际不符.注意的是,每个条件都要指定排序规则,上例中用户名就不区分大小写.
  6.Order By的一个小技巧
  Order By可以指定列序而不用指定列名,在下面的例子里说明它的用处(注意,第三列未指定别名)
  Select a.ID,a.Name,(Select Count(*) From TableB b Where a.ID=b.PID) From TableA a Order By 3

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